Задания для самостоятельной работы 2008 change = change / 100 ! ! Boundary potential ! boundary_potential_x : do i = 1, nx v(i, 1) = v0 ; v(i, ny) = v0 end do boundary_potential_x boundary_potential_y : do j = 1, ny v(1, j) = v1 ; v(nx, j) = v1 end d
{}