AOE Aerospace and Ocean Engineering Fall 2009
{"Image DocumentName": "AOE Aerospace and Ocean Engineering Fall 2009", "Image ImageDescription": "Wind Tunnels \u2013 Sample Problem 1 Solution. Height of liquid: Dh = 10cm = 0.1m. Specific weight of liquid mercury: w = (1.36x104)x9.8 = 1.33x105 N/m2. Actual pressure difference: p1-p2 = w Dh = 1.33x104 N/m2. To find V2 from Bernoulli, use. We computed p1-p2, A1/A2 = 15 is given, so we need to find r. Since we are in a low-speed wind tunnel, flow is incompressible, so r = const, which means we can compute it at any point in the tunnel. Since p1 and T1 are given, use Equation of State to find r = r 1: Combining all the results we get V2 = 144 m/s (slightly over the incompressible velocity limit, which means compressibility effects should be taken into account). Virginia Tech. Lecture 2. 1 September 2009.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}