Hess's Law Example 15-7: Given the following equations and Hovalues
{"Image DocumentName": "Hess\u2019s Law Example 15-7: Given the following equations and \uf044Ho\uf020values", "Image ImageDescription": "calculate \uf044Ho for the reaction below. N2O (g) + NO2(g) \uf022 3 NO(g) \uf044Ho= ? [1] 2N2(g) + O2(g) \uf022 2 N2O(g) \uf044Ho= kJ. [2] N2(g) + O2(g) \uf022 2 NO(g) \uf044Ho= kJ. [3] N2(g) + 2 O2(g) \uf022 2NO2(g) \uf044Ho= 66.4 kJ. \u00bd [-1] + 3/2 [2] + \u00bd [-3] \u00bd [-1] N2O(g) \uf022 N2(g) + \u00bd O2(g) \uf044Ho= \u00bd x (-164.1) kJ. 3/2 [2] 3/2 N2(g) + 3/2 O2(g) \uf022 3 NO(g) \uf044Ho= 3/2 x (180.5) kJ. \u00bd [-3] NO2(g) \uf022 \u00bd N2(g) + O2(g) \uf044Ho= \u00bd (-66.4) kJ. N2O (g) + NO2(g) \uf022 3 NO(g) \uf044Ho= (-82.05) (-33.2) = kJ (endothermic reaction)", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}