Since we know ω3, we can find VB. B is a point on link 3:
{"Image DocumentName": "Since we know \u03c93, we can find VB. B is a point on link 3:", "Image ImageDescription": "Finding \u03c94, knowing \u03c93. Instant Centers for a Four-bar. Finding velocities. Since we know \u03c93, we can find VB. B is a point on link 3: VB = \u03c93 \u2219 RBI1,3. Its direction is obtained by rotating RBI1,3 90\u00b0 in the direction of \u03c93. B is also a point on link 4 which yields: VB = \u03c94 \u2219 RBI1,4. We already know VB so we can solve for \u03c94: \u03c94 = VB \u2215 RBI1,4. VB. \u03c93. VA. B = I3,4. A = I2,3. I2,4. RBI4,1. \u03c92. \u25ba O2 = I1,2. \u03c94. O4= I4,1. RBI1,3. \u25ba I1,3.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}