Chemical Kinetics Second-Order Processes Integrating the rate law for a process that is second-order in reactant A, we get 1 [A] t = kt + 1 [A] o also
{"Image DocumentName": "Second-Order Processes", "Image ImageDescription": "Integrating the rate law for a process that is second-order in reactant A, we get. 1. [A]t. = kt + [A]o. also in the form, y = mx + b.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}