Agents Ca0 + 2 H+1Cl-1  Ca+2Cl-12 + H20
{"Image DocumentName": "Agents Ca0 + 2 H+1Cl-1 \uf0ae Ca+2Cl-12 + H20", "Image ImageDescription": "Since Ca0 is being oxidized and H+1 is being reduced, the electrons must be going from the Ca0 to the H+1. Since Ca0 would not lose electrons (be oxidized) if H+1 weren\u2019t there to gain them, H+1 is the cause, or agent, of Ca0\u2019s oxidation. H+1 is the oxidizing agent. Since H+1 would not gain electrons (be reduced) if Ca0 weren\u2019t there to lose them, Ca0 is the cause, or agent, of H+1\u2019s reduction. Ca0 is the reducing agent.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}