Higher Grade Chemistry Calculation of excess Calculations for you to try. 2.What mass of hydrogen is formed when 3.27g of zinc is reacted with 25cm 3
{"Image DocumentName": "Calculation of excess Calculations for you to try.", "Image ImageDescription": "What mass of hydrogen is formed when 3.27g of zinc is reacted with 25cm3 of 2 mol l-1 hydrochloric acid? Zn + 2HCl \uf0e0 ZnCl2 + H2. Zn + 2HCl \uf0e0 ZnCl2 + H2. 1 mol 2 mol. Number of moles of Zn in 3.27 g = 3.27/65.4 = Number of moles of HCl = 2 x 25/1000 = From equation 1 mol of Zn reacts with 2 mol of HCl . So 0.05 mol of Zn reacts with 0.1 mol of HCl . As we have only 0.05 mol of HCl it is the zinc that is in excess. All 0.05 mol of HCl is used up. From equation 0.05 mol of HCl will produce 0.5 x 0.05 mol H mol of H2 weighs x 2 = 0.05 g. Higher Grade Chemistry.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}