The Gradient of a Tangent
{"Image DocumentName": "The Gradient of a Tangent", "Image ImageDescription": "Step 2 : Finding the coordinates at the point. At the point x = 2 the function value is given by. y = 3 (2)3 \u2013 y = 3(8) + 4. y = 28. The coordinate is therefore the point (2, 28)", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}