Exercise The value of Hvaporization of substance X is 45.7 kJ/mol, and its normal boiling point is 72.5°C.
{"Image DocumentName": "ExerciseThe value of \uf044Hvaporization of substance X is 45.7 kJ/mol, and its normal boiling point is 72.5\u00b0C.", "Image ImageDescription": "Calculate \uf044S, \uf044Ssurr, and \uf044G for the vaporization of one mole of this substance at 72.5\u00b0C and 1 atm. \uf044S = 132 J/K\u00b7mol. \uf044Ssurr = -132 J/K\u00b7mol. \uf044G = 0 kJ/mol. \uf044S = 132 J/K\u00b7mol. \uf044Ssurr = -132 J/k\u00b7mol. \uf044G = 0 kJ/mol. Copyright \u00a9 Cengage Learning. All rights reserved.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}