After adding 100 mL Ce4+ (end point): the two potentials are identical
{"Image DocumentName": "After adding 100 mL Ce4+ (end point): the two potentials are identical", "Image ImageDescription": "E = EO /1 log [Fe3+]/[Fe2+]= 0.77 V. E = EO /1 log [Ce4+]/[Ce3+]= 1.45 V. Summation of two equations: 2 E = Eo1 + Eo log. [Fe3+][Ce4+] [Fe2+][Ce3+] At the end point: Fe2+ = Ce4+ , and Fe3+ = Ce3+ 2 E = Eo1 + Eo2. E = ( Eo1 + Eo2 ) / 2 E = / 2 = 1.10 V.", "Image XResolution": "37", "Image YResolution": "37", "Image ResolutionUnit": "Pixels/Centimeter", "Image Software": "SlidePlayer", "Image YCbCrPositioning": "Centered"}